{"id":2265,"date":"2026-06-23T06:50:58","date_gmt":"2026-06-23T06:50:58","guid":{"rendered":"https:\/\/helicalcutgears.top\/?p=2265"},"modified":"2026-06-23T06:50:58","modified_gmt":"2026-06-23T06:50:58","slug":"why-do-helical-gears-have-axial-thrust","status":"publish","type":"post","link":"https:\/\/helicalcutgears.top\/cs\/why-do-helical-gears-have-axial-thrust\/","title":{"rendered":"Pro\u010d maj\u00ed \u0161ikm\u00e1 ozuben\u00e1 kola axi\u00e1ln\u00ed axi\u00e1ln\u00ed s\u00edlu? Kompletn\u00ed technick\u00e9 vysv\u011btlen\u00ed s praktick\u00fdm p\u0159\u00edkladem"},"content":{"rendered":"
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Pro\u010d maj\u00ed \u0161ikm\u00e1 ozuben\u00e1 kola axi\u00e1ln\u00ed axi\u00e1ln\u00ed s\u00edlu? Kompletn\u00ed technick\u00e9 vysv\u011btlen\u00ed<\/h1>\n

Axi\u00e1ln\u00ed axi\u00e1ln\u00ed posuv ozuben\u00fdch kol je jedn\u00edm z nej\u010dast\u011bji kladen\u00fdch technick\u00fdch t\u00e9mat pro konstrukt\u00e9ry ozuben\u00fdch pohon\u016f \u2013 ne proto, \u017ee by byl slo\u017eit\u00fd, ale proto, \u017ee je t\u0159eba spole\u010dn\u011b ch\u00e1pat jeho p\u016fvod v geometrii zubu, jeho sm\u011br vzhledem ke spir\u00e1le a jeho d\u016fsledky pro v\u00fdb\u011br lo\u017eiska. Tento \u010dl\u00e1nek se zab\u00fdv\u00e1 v\u0161emi t\u0159emi t\u00e9maty, v\u010detn\u011b zpracovan\u00e9ho numerick\u00e9ho p\u0159\u00edkladu a t\u0159\u00ed osv\u011bd\u010den\u00fdch technick\u00fdch \u0159e\u0161en\u00ed.<\/p>\n

Proberte v\u00fdb\u011br lo\u017eiska pro v\u00e1\u0161 pohon \u2192<\/a><\/p>\n<\/div>\n<\/div>\n

Kr\u00e1tk\u00e1 odpov\u011b\u010f \u2013 Pro\u010d vznik\u00e1 axi\u00e1ln\u00ed tah<\/h2>\n

Zub \u010deln\u00edho ozuben\u00e9ho kola je rovnob\u011b\u017en\u00fd s osou h\u0159\u00eddele \u2013 kontaktn\u00ed s\u00edla zubu p\u016fsob\u00ed pouze v rovin\u011b ot\u00e1\u010den\u00ed (tangenci\u00e1ln\u00ed a radi\u00e1ln\u00ed slo\u017eka, nulov\u00e1 axi\u00e1ln\u00ed slo\u017eka). A spir\u00e1lov\u00e9 ozuben\u00e9 kolo<\/strong> Zub je naklon\u011bn pod \u00fahlem \u03b2 k ose h\u0159\u00eddele. Kdy\u017e zub p\u0159en\u00e1\u0161\u00ed zat\u00ed\u017een\u00ed, kontaktn\u00ed s\u00edla pod\u00e9l naklon\u011bn\u00e9ho zubu p\u016fsob\u00ed pod \u00fahlem \u03b2 od p\u0159\u00ed\u010dn\u00e9 roviny \u2013 a slo\u017eka t\u00e9to s\u00edly rozlo\u017een\u00e1 pod\u00e9l osy h\u0159\u00eddele je axi\u00e1ln\u00ed axi\u00e1ln\u00ed s\u00edla. \u010c\u00edm v\u011bt\u0161\u00ed je \u00fahel stoup\u00e1n\u00ed \u0161roubovice \u03b2, t\u00edm v\u011bt\u0161\u00ed je axi\u00e1ln\u00ed axi\u00e1ln\u00ed s\u00edla vzhledem k p\u0159en\u00e1\u0161en\u00e9 tangenci\u00e1ln\u00ed s\u00edle.<\/p>\n

Fyzika \u2014 rozli\u0161en\u00ed sil na spir\u00e1lov\u00e9m zubu<\/h2>\n

V bod\u011b stoup\u00e1n\u00ed spir\u00e1lov\u00e9 ozuben\u00e9 kolo<\/strong> P\u0159i p\u0159en\u00e1\u0161en\u00e9m kroutic\u00edm momentu T p\u016fsob\u00ed na kontaktn\u00ed oblast zubu t\u0159i vz\u00e1jemn\u011b kolm\u00e9 slo\u017eky s\u00edly:<\/p>\n

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Slo\u017eka s\u00edly<\/th>\nSymbol<\/th>\nVzorec<\/th>\nSm\u011br<\/th>\nP\u016fsob\u00ed na<\/th>\n<\/tr>\n<\/thead>\n
Tangenci\u00e1ln\u00ed s\u00edla<\/td>\nF_t<\/td>\nF_t = 2T \/ d = 2T cos \u03b2 \/ (M_n \u00d7 z)<\/td>\nTe\u010dna k rozte\u010dn\u00e9 kru\u017enici, kolm\u00e1 k ose h\u0159\u00eddele<\/td>\nP\u0159en\u00e1\u0161\u00ed to\u010div\u00fd moment \u2013 \u200b\u200b\u201eu\u017eite\u010dnou\u201c slo\u017eku<\/td>\n<\/tr>\n
Radi\u00e1ln\u00ed s\u00edla<\/td>\nF_r<\/td>\nF_r = F_t \u00d7 tan \u03b1_n \/ cos \u03b2<\/td>\nRadi\u00e1ln\u011b sm\u011brem ven od st\u0159edov\u00e9 osy h\u0159\u00eddele<\/td>\nOdd\u011bluje dva p\u0159evody \u2013 zat\u011b\u017euje radi\u00e1ln\u00ed lo\u017eiska<\/td>\n<\/tr>\n
Axi\u00e1ln\u00ed tah<\/td>\nF_a<\/td>\nF_a = F_t \u00d7 tan \u03b2<\/strong><\/td>\nRovnob\u011b\u017en\u011b s osou h\u0159\u00eddele \u2013 zdroj probl\u00e9mu<\/td>\nZat\u00ed\u017een\u00ed axi\u00e1ln\u00edch lo\u017eisek; mus\u00ed b\u00fdt absorbov\u00e1no pouzdrem<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

Kl\u00ed\u010dov\u00fdm vztahem je vzorec pro axi\u00e1ln\u00ed tah F_a = F_t \u00d7 tan \u03b2. V\u0161imn\u011bte si, \u017ee:<\/p>\n