{"id":2265,"date":"2026-06-23T06:50:58","date_gmt":"2026-06-23T06:50:58","guid":{"rendered":"https:\/\/helicalcutgears.top\/?p=2265"},"modified":"2026-06-23T06:50:58","modified_gmt":"2026-06-23T06:50:58","slug":"why-do-helical-gears-have-axial-thrust","status":"publish","type":"post","link":"https:\/\/helicalcutgears.top\/sk\/why-do-helical-gears-have-axial-thrust\/","title":{"rendered":"Pre\u010do maj\u00fa \u0161pir\u00e1lov\u00e9 ozuben\u00e9 koles\u00e1 axi\u00e1lny tlak? Kompletn\u00e9 technick\u00e9 vysvetlenie s praktick\u00fdm pr\u00edkladom"},"content":{"rendered":"
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Pre\u010do maj\u00fa \u0161pir\u00e1lov\u00e9 ozuben\u00e9 koles\u00e1 axi\u00e1lny \u0165ah? Kompletn\u00e9 technick\u00e9 vysvetlenie<\/h1>\n

Axi\u00e1lny \u0165ah \u0161pir\u00e1lov\u00e9ho ozuben\u00e9ho kolesa je jednou z naj\u017eiadanej\u0161\u00edch technick\u00fdch t\u00e9m pre kon\u0161trukt\u00e9rov ozuben\u00fdch pohonov \u2013 nie preto, \u017ee je zlo\u017eit\u00fd, ale preto, \u017ee jeho p\u00f4vod v geometrii zuba, jeho smer vzh\u013eadom na stranu \u0161pir\u00e1ly a jeho d\u00f4sledky pre v\u00fdber lo\u017eiska je potrebn\u00e9 ch\u00e1pa\u0165 spolo\u010dne. Tento \u010dl\u00e1nok sa zaober\u00e1 v\u0161etk\u00fdmi tromi t\u00e9mami, pri\u010dom uv\u00e1dza pracn\u00fd numerick\u00fd pr\u00edklad a tri overen\u00e9 technick\u00e9 rie\u0161enia.<\/p>\n

Diskutujte o v\u00fdbere lo\u017eiska pre v\u00e1\u0161 pohon \u2192<\/a><\/p>\n<\/div>\n<\/div>\n

Stru\u010dn\u00e1 odpove\u010f \u2013 Pre\u010do vznik\u00e1 axi\u00e1lny \u0165ah<\/h2>\n

Zub ozuben\u00e9ho kolesa s \u010deln\u00fdm ozuben\u00fdm kolesom je rovnobe\u017en\u00fd s osou hriade\u013ea \u2013 kontaktn\u00e1 sila zuba p\u00f4sob\u00ed iba v rovine ot\u00e1\u010dania (tangenci\u00e1lna a radi\u00e1lna zlo\u017eka, nulov\u00e1 axi\u00e1lna zlo\u017eka). A \u0161pir\u00e1lov\u00e9 ozuben\u00e9 koleso<\/strong> Zub je naklonen\u00fd pod uhlom \u03b2 k osi hriade\u013ea. Ke\u010f zub pren\u00e1\u0161a za\u0165a\u017eenie, kontaktn\u00e1 sila pozd\u013a\u017e naklonen\u00e9ho zuba p\u00f4sob\u00ed pod uhlom \u03b2 od prie\u010dnej roviny \u2013 a zlo\u017eka tejto sily rozlo\u017een\u00e1 pozd\u013a\u017e osi hriade\u013ea je axi\u00e1lna sila. \u010c\u00edm v\u00e4\u010d\u0161\u00ed je uhol skrutkovice \u03b2, t\u00fdm v\u00e4\u010d\u0161ia je axi\u00e1lna sila v porovnan\u00ed s pren\u00e1\u0161anou tangenci\u00e1lnou silou.<\/p>\n

Fyzika \u2014 rozl\u00ed\u0161enie sily na \u0161pir\u00e1lovom zube<\/h2>\n

V bode st\u00fapania \u0161pir\u00e1lov\u00e9 ozuben\u00e9 koleso<\/strong> Pri pren\u00e1\u0161anom kr\u00fatiacom momente T p\u00f4sobia na kontaktn\u00fa z\u00f3nu zuba tri vz\u00e1jomne kolm\u00e9 zlo\u017eky sily:<\/p>\n

\n\n\n\n\n\n\n\n
Zlo\u017eka sily<\/th>\nSymbol<\/th>\nVzorec<\/th>\nSmer<\/th>\nSkutky<\/th>\n<\/tr>\n<\/thead>\n
Tangenci\u00e1lna sila<\/td>\nF_t<\/td>\nF_t = 2T \/ d = 2T cos \u03b2 \/ (M_n \u00d7 z)<\/td>\nTangenta k rozstupovej kru\u017enici, kolm\u00e1 na os hriade\u013ea<\/td>\nPren\u00e1\u0161a kr\u00fatiaci moment \u2013 \u200b\u200b\u201eu\u017eito\u010dn\u00fa\u201c zlo\u017eku<\/td>\n<\/tr>\n
Radi\u00e1lna sila<\/td>\nF_r<\/td>\nF_r = F_t \u00d7 tan \u03b1_n \/ cos \u03b2<\/td>\nRadi\u00e1lne smerom von od stredovej \u010diary hriade\u013ea<\/td>\nOdde\u013euje dva ozuben\u00e9 koles\u00e1 \u2013 za\u0165a\u017euje radi\u00e1lne lo\u017eisk\u00e1<\/td>\n<\/tr>\n
Axi\u00e1lny \u0165ah<\/td>\nF_a<\/td>\nF_a = F_t \u00d7 tan \u03b2<\/strong><\/td>\nRovnobe\u017ene s osou hriade\u013ea \u2013 zdroj probl\u00e9mu<\/td>\nZa\u0165a\u017eenie axi\u00e1lnych lo\u017e\u00edsk; mus\u00ed by\u0165 absorbovan\u00e9 telesom<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

K\u013e\u00fa\u010dov\u00fdm vz\u0165ahom je vzorec pre axi\u00e1lny \u0165ah F_a = F_t \u00d7 tan \u03b2. V\u0161imnite si, \u017ee:<\/p>\n